This will be a talk for the CUNY Set Theory Seminar, March 6, 2015.
I shall describe the current state of knowledge concerning the question of whether there can be an embedding of the set-theoretic universe into the constructible universe.
Question.(Hamkins) Can there be an embedding
The notion of embedding here is merely that
Nevertheless, the question arises very naturally in the context of my previous work on the embeddability phenomenon, Every countable model of set theory embeds into its own constructible universe, where the title theorem is the following.
Theorem.(Hamkins) Every countable model of set theory
The methods of proof also established that the countable models of set theory are linearly pre-ordered by embeddability: given any two models, one of them embeds into the other; or equivalently, one of them is isomorphic to a submodel of the other. Indeed, one model
In the proof of that theorem, the embeddings
Currently, the question remains open, but we have some partial progress, and have settled it in a number of cases, including the following, on which I’ll speak:
- If there is an embedding
, then for a proper class club of cardinals , we have . - If
exists, then there is no embedding . - If
exists, then there is no embedding and indeed no embedding . - If there is an embedding
, then the GCH holds above . - In the forcing extension
obtained by adding many Cohen reals (or more), there is no embedding , and indeed, no . More generally, after adding many Cohen subsets to , for any regular cardinal , then in there is no . - If
is a nontrivial set-forcing extension of an inner model , then there is no embedding . Indeed, there is no embedding , if the forcing has size . In particular, if is a nontrivial forcing extension, then there is no embedding . - Every countable set
has an embedding .
This is joint work of myself, W. Hugh Woodin, Menachem Magidor, with contributions also by David Aspero, Ralf Schindler and Yair Hayut.
See my related MathOverflow question: Can there be an embedding